化简:11+x+21+x2+41+x4+…+n1+xn-2n1-x2n. 答案:考点:分式的加减法
专题:
分析:在原式中补项是其与第2项合并,进而再和第3项合并,最后得出答案.
解答:解:11+x+21+x2+41+x4+…+n1+xn-2n1-x2n,=-11-x+11-x+11+x+21+x2+41+x4+…+n1+xn-2n1+x2n,=-11-x+1+x(1+x)(1-x)+1-x(1+x)(1-x)+21+x2+41+x4+…+n1+xn-2n1+x2n,=-11-x+1+x+1-x(1+x)(1-x)+21+x2+41+x4+…+n1+xn-2n1+x2n,=-11-x+21-x2+21+x2+41+x4+…+n1+Most of us
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