某人造地球卫星绕地球做匀速圆周运动,其轨道半径为地球半径R的3倍,已知地面附近的重力加速度为g,引力常量为G,求这颗人造地球卫星的向心加速度和周期. 答案:=g. T=6 (2分) 解析: 解:设地球的质量为M,人造地球卫星的质量为m,由万有引力定律有 G=m (3分) 在地面附近有 mg=G She tried to finish all the work in one day but finally _____ and had to take a rest. A. broke away B. broke up C. broke down D. broke out