1图
2图
Private Sub Command1_Click()
Dim x1 As Integer, x2 As Integer, n As Integer
Dim sum As Long
x1 = Val(Text1.Text)
x2 = Val(Text2.Text)
Sum = 0
If x1 < x2 Then n = 1 Else
For i = x1 To x2 Step n
If Then
Sum = Sum + i
Next i
Label3.Caption = "从" & x1 & "到" & x2 & "之间所有奇数的累加和=" & Str(Sum)
End Sub
For i=1 To 3
k=“”
Fori-1 To 2*i-1
k=k+“*”
Next j
List1.AddItem k
Next i
该程序运行后,在列表框List1中显示的是( )
Private Sub Cmd1_Click()
Dim s As String, c As String
Dim flag As Boolean
Dim i As Integer,count As Integer
s=Text 1.Text
flag=True
For i=1 To Len(s) -1
c=Mid(s,i,2)
If c=“**”Then
①
Exit For
End If
Next i
s=“#”+s·“#”
count =0:i= 2
Do While flag And i<=Len(s) -1
If ② Then
s=Mid(s,1,i-1) +“*”+Mid(s, i+1, Len(s) -i)
③
End If
i=i+1
Loop
If Not flag Then
Label2.Cnption=“警告!“
Elself count = 0 Then
Label2.Caption=“该排人数己满”
Else
Label2.Caption=“该排至多还能有”+Str(count) +“个人入座”
End If
End Sub
① ② ③
import pandas as pd
df1=pd. DataFrame([[10, 20], [30, 40]], columns=['A','B'])
df2=pd. DataFrame([50, 60], [70, 80]], columns=['A',B'])
df=df1. append(df2,ignore_ index= True)
print(df)
该程序段运行后输出结果为( )
Const n = 5
Dim b(n)As Integer
For i = 1 To 5
b(i)= i
Next i
For i = 1 To 2
For j = n – 1 To I Step -1
If a(b(j))> a(b(j + 1))Then
t = b(j):b(j)=b(j + 1):b(j + 1)= t
End If
Next j
Next i
数组元素a(1)~a(5)的值依次为“35,24,45,16,77”,运行上述程序段后,数组元素b(1)到b(5)的值依次为( )
Dim a(1 to 10) As Integer ‘存储原始数据
Dim b(1 to 10)As Integer ‘存放名次
Private Sub Command1_Click()
Dim i As Integer, j As Integer, n As Integer
For i=1 To 10 n=0
For j=1 To 10
If Then
Next j
Next i
b(i)= n
For i= 1 to 10
List2.Additem str(a(i))&“ ”&
Next i
End Sub
Private Sub Form_Load()
‘随机产生 10 个[60,100]之间的随机数,并显示在 List1 中,代码略。
End Sub
For i=1 To 10
b(a(i) Mod 10)= b(a(i) Mod 10)+1
b(a(i)\10)=b(a(i)\10)+1
Next i
num=0
For i=0 To 9
If b(i)>num Then num b(i)
Next i
数组b各元素初始值为0,数组元素a(1)到a(10)的值依次为“68,17,24,30,36,40,55,58,61,66”,执行该程序段,num的值为( )
Private Sub Command1_Click()
Dim i AS Integer
Dim As Long
For i = 1 To 100
s = s + i *(i+1)
Nest i
Text1. Caption = s
End Sub
Private Sub Command1_ Click()
Dim i As Integer
Dim As String
i= Text1.Text
If i/7=0 Then '判断文本框中输入的数是否是7的倍数
j=i & “是7的倍数,能被7整除! ” '是7的倍数,输出能被7整除!
Else
j=i&"不是7的倍数,不能被7整除!" '不是7的倍数,就输出不是7的倍数,不能被7整除!!
EndIf
Label3. Caption=j
End Sub
x=0: y=0
For n=1 To 5
x=x+1
y=y+1
Next n
Print x+y
s =“312321”:m=0:c=“”:k=1
For i=1 To Len(s)
m=m+k
If k=1 Then c=Mid(s,n,1)+c Else c=c+ Mid(s,m,1)
If i Mod 3=0 Then k=-k:m=Len(s)+1
Next i
执行该程序段后。变量c的值是( )
Dim x As Integer,s As String,t As Integer
x=Val(Text1.Text)
Do While x>0
Loop
Label1.Caption= s
方框中的代码由以下三部分组成:
①x=x\2
②s=Str(t)+s
③t=x Mod 2
代码顺序正确的选项是( )
求T值的方法如下:取某个灰度值k,将图像所有N个像素分成两类,灰度值小于k的作为背景像素,灰度值大于等于k 的作为前景像素,统计两类像素的个数分别为N1、N2,计算灰度值的均值分别为μ1、μ2,利用公式 计算出两类像素的差异值。当该值最大时,k即为要找的最佳灰度值T。若某区间段内有连续多个T满足要求,则T取中间值。
例如:图a所示图像像素的灰度值仅为0~5,统计0~5灰度值像素的个数依次为8、7、2、6、9、4,如图b所示。当k=2时,N1=15,N2=21,μ1=(0*8+1*7)/(8+7),μ2=(2*2+3*6+4*9+5*4)/(2+6+9+4),计算出差异值为2.5635。依此类推,计算差异值如图c所示。可知,当k=3时差异值最大,3是最佳灰度值T。
编写VB程序,实现如上功能。读取图像所有像素的灰度值后,单击按钮Command1,在标签Label1上显示T值。
Const N = 32 * 24
Dim a(1 To N) As Integer 'a 数组存储图像所有像素的灰度值
Private Sub Form_Load()
'读取图像中的所有像素的灰度值存入a数组,代码略
End Sub
Private Sub Command1_Click()
Dim i As Integer, j As Integer, k As Integer
Dim sum As Long, sum1 As Long, N1 As Long, N2 As Long
Dim μ1 As Double, μ2 As Double, diff As Double, max_var As Double
Dim t1 As Integer, t2 As Integer, T As Integer
Dim h(255) As Long
Dim c(255) As Long
max_var = 0: t1 = 0: t2 = 0: N1 = 0: N2 = 0: sum = 0: sum1 = 0
For i = 0 To 255
h(i) = 0: c(i) = 0
Next i
For i = 1 To N
h(a(i)) = h(a(i)) + 1
Next i
c(0) = h(0)
For i = 1 To 255
'统计灰度值小于等于i 的像素个数
sum = sum + i * h(i)
Next i
For k = 1 To 255
N1 = c(k - 1)
N2 = N - N1
If N1 <> 0 And N2 <> 0 Then
μ1 = sum1 / N1
μ2 = (sum - sum1) / N2
diff = N1 / N * N2 / N * (μ1 - μ2) ^ 2
diff = Round(diff, 4) 'Round 函数的作用是对diff 保留四位小数
If diff >= max_var Then
t1 = k
If diff > max_var Then
max_var = diff
End If
End If
Next k
T = (t1 + t2) \ 2
Label1.Caption = "将该图像分割为前景与背景两部分的最佳灰度值为:" & T
End Sub
a={"张三":80,"李四":85,"王五":90,"赵六":70,"钱七":65}
b=input("请输入姓名:")
fenshu= #从字典读取分数
样例: 请输入字符串: bcabc 字符串环中的最长回文字符串是: bcb |
import sys
def ishw(s): #判断s是否是回文字符串
if s==
return True
else:
return False
s = input("请输入字符串: ")
n = len(s)
s=s+s
for i in range(n, 0, -1): # 枚举字符串长度
for j in
t=s[j:j+i]
if ishw(t):
print(“字符串环中的最长回文字符串是:”+ t)
sys.exit(0) #提前结束程序
dic={ "2":1,"6":2,"8":3,"4":-2 }
cp=input("请输入车牌号(格式如“浙H94286”):")
count=0
for i in range(2, ① ):
x=cp[i]
if x in ["2","4","6","8"]:
count+= ②
print("该车牌号的吉利值为:",count)
为实现功能,划线处代码应为( )
h=
s=input('触地前的发光颜色变化:')
d={'R':0.8,'G':0.6,'B':0.5}
sum=h
for i in range(1,len(s)):
h=d[c]*h
sum=
print('弹球发光状态下的运动轨迹长度:'+str(sum))
Private Sub Commaadl Click()
Dim xm As String,xmmax as String ,xmmin as String
Dim cj As Single,cjmax As Single,cjmin As Single
xm=InputBox("请输人学生姓名")
cj=InputBox("请输人学生成绩")
xmmax=xm
cjmax=cj
xmmin=xm
cjmin=cj
Do While
If Then
cjmax=cj
xmmax=xm
End if
If Then
cjmin = cj
xmmin=xm
End if
xm=InputBox("请输人学生姓名")
cj=InputBox("请输人学生成绩")
Label1.Caption ="学生"&xmmax&"成绩最高”&cjmax
Label2.Caption ="学生"&xmmin &“成绩最低"& ejmin
End Sub
for i in range(1,3):
for j in range(1,4):
print(i*j,end='')