Private Sub Command1_Click()
Dim i As Integer
Dim a(10)As Integer ‘①
For i=1 To 10 ‘②
a(i)=Rnd* 100 ‘③
Next i
Label1.Caption=Str(a(i)) ‘④
End Sub
a(I)=68: a(2)=88: a(3)=76: a(4)= 60: a(5)=98: a(6)=100: a(7)= 64: a(8)=85: a(9)=99: a(10)=59
For i=1 To 9
b(i)=Abs(a(i+1)-a(i))
c(b(i)\10)= c(b(i)\10) + 1
Next i
For i=0 To 10
If c(i)> 0 Then Label1.Caption = Label1.Caption + "" + Str(c(i))
Next i
数组c各元素初值为0,执行该程序段,标签Label 1上显示的内容是( )
Private Sub Command1_click ( )
Dim i As Integer, n As Integer
Dim s1 As String, s2 As string, c As String
s1 = Text1. Text: s2 = “”
For i = 1 To Len(s1)
c = Mid (s1, i, 1)
If c > = “a" And c < = “z” Then s2 = c+s2
Next i
Text2. Text = s2
End sub
该程序运行时,在文本框Text1中输入”Flash CS33”(不包含””),单击命令按钮Command1后,文本框Text2中显示的内容是( )
s=Text 1.Text
t=“”
For i=1ToLen(s)
c=Mid(s,i,1)
If c<“a”Or c>“z”The nt=“”
t=c+t
Next i
Label 1.Caption=t
执行此程序段时,在文本框Text 1中输入“2020NihaoWolaile”,则标签Label 1中显示的内容是( )
Dim Sum As Long
Dim i As Long
Sum=0
i=0
Do While Sum<10
i=i+1
Sum=Sum+i*i
Loop
Print Sum
t = "abcd123456"
x = Sqr(Len(t))
y = 0
If x >0 Then
y = 2
ElseIf x >1 Then
y = 3
ElseIf x >2 Then
y = 4
Else
y = 5
End If
a(1) = 1
For i = 2 To 6
a(i)=a(i-1)+Int(Rnd*5+1)
If a(i) Mod 2 = 1 Then
a(i) = a(i) \2 + 1
Else
a(i) = a(i) / 2
End If
Next i
执行程序后,a数组各元素可能是( )
校验码的计算方法如下:
①将身份证号码的前17位数字分别乘以对应的系数。对应关系如下:
号码位 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
13 |
14 |
15 |
16 |
17 |
系数 |
7 |
9 |
10 |
5 |
8 |
4 |
2 |
1 |
6 |
3 |
7 |
9 |
10 |
5 |
8 |
4 |
2 |
②将17位数字和系数相乘的结果累计求和;
③用所求的和除以11得到余数;
④用余数与身份证号码的最后一位校验码进行对应,对应关系如下:
余数 |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
校验码 |
1 |
0 |
X |
9 |
8 |
7 |
6 |
5 |
4 |
3 |
2 |
ID=input("请输入十八位身份证号码: ")#输入身份证号码
sex={0:"女",1:"男",2:"女",3:"男",4:女,5:"男": 6:"女",7:"男"."8:"女",9:"男"}
ID_ birth=ID[6:14]
ID_ sex=ID[16]
ID_ check=ID[17]
#求出year,month,day
① |
print("出生日期: "+year+"年"+ month+"月"+day+"日")
print("性别:", ② )
ID=list(ID) #把字符串转成列表
ID=list(map(int, ID[0:17])) #把前17个元素转成整型
ID_ CHECK=["1","0'","X'","9“,"8","7”,"6“,"5”,"4","3","2"]
③ |
#用列表存储每一位权值 #17位数字和系数相乘的结果累计求和 #求余数 #求验证码 |
print("验证码是否正确:", check-= =ID_check)
s=0: x=0
For k = 3 To 1 Step -1
If k <= 1 Then x = 1
If k <= 2 Then x = 2
If k <= 3 Then x = 3
s = s + x
Next k
该程序段运行后,变量s的值是( )
b = 5
k = 0: imax = 0
For i = 1 To 20
If a(i) = b Then
k = k + 1
If ⑴ Then
imax = k
⑵
End If
Else
k = 0
End If
Next i
Label1.Caption = "最大长度:" +Str(imax) +",起始位置:" + Str(st)
划线处可选代码为:
①k > imax ② k >= imax ③ st = i - imax + 1 ④ st = i
下列选项中,代码顺序正确的是( )
数字字符 |
0 |
1 |
... |
7 |
8 |
9 |
|||||||||||||||
二进制值 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
1 |
... |
0 |
1 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
1 |
十进制值 |
0 |
0 |
0 |
1 |
... |
1 |
3 |
2 |
0 |
2 |
1 |
||||||||||
对应编码 |
A |
A |
A |
B |
... |
B |
D |
C |
A |
C |
B |
||||||||||
例如, 数字字符串“709”的编码为“BDAACB”。用VB程序实现上述编码,功能如下:在文本框Text1中输入编码的一串数字字符,单击“编码”命令按钮Command1,在文本框Text2中显示编码结果。程序运行界面如图所示。
Private Sub Command1_Click( )
Dim code As String, s As String, ch As String, result As String
Dim i As Integer, numL As Integer, numR As Integer
Dim flag As Boolean
code = "ABCD"
s = Text1.Text
flag = True
result = ""
For i = 1 To
If ch < "0" Or ch > "9" Then
flag = False
Exit For ' 退出循环
Else
numL = Val(ch) \ 4
numR =
result = result + Mid(code, numL + 1, 1) +
End If
Next i
If flag Then
Text2.Text = result
Else
Text2.Text = "输入错误"
End If
End Sub
Private Sub Command1_Click()
Dim s As String, f As Boolean, L As Integer
s = Text1.Text
j = Len(s)
i = 1
Do while
i = i+1
j = j-1
Loop
If Then Print "是回文串" Else Print " 不是回文串"
End Sub
在画线处填入合适代码,使程序能正常运行。
大于等于90分为A;
小于90且大于等于80为B;
小于80且大于等于70为C;
小于70且大于等于60为D;
小于60为E。
if fenshu>=90: #变量fenshu表示分数
grade="A"
grade="B"
elif fenshu >=70:
grade="C"
elif fenshu >=60:
grade="D"
else:
grade="E"
#输出等第
def f(a,b):
if a>b:
return a-b return a+b
x1=int(input("请输入第一个数"))
x2=int(input("请输入第二个数"))
print(f(f(x1,x2),f(x2,x1)))
当键盘输入12和13后,程序输出的结果是( )
s=0
for i in range(9):
if i%3==0:
s+=i
print(s)
张老师想了解每个小方格被多少块地毯覆盖,以便更好地调整地毯铺设位置,他编写了VB程序,实现以下功能:在文本框Text1中输人行数m,在文本框Text2中输入列数n,在Text3中输入每块地毯铺设的坐标x1,y1,x2,y2……坐标之间逗号分隔,地毯数量不超过100),单击计算按钮Commmand1,在列表框List1中显示每个小方格被多少块地毯覆盖。程序运行界面如图所示。
Dim m As Integer
Dim n As Integer
Dim a, b, C, d As Integer
Dim flag(0 To 10000) As Integer
Dim sum(0 To 10000) As Integer
Dim pos(0 To 100) As Integer
Private Sub Command1_Click()
List1. Clear
m = Val(Text1. Text)
n = Val(Text2. Text)
s = Text3. Text
'读取每块地毯坐标,并按顺序存储在pos数组中
'地毯总数量存储在变量k中
For i=1 To k
a= pos(i * 4- 3):b= pos(i * 4- 2):c= pos(i * 4- 1):d= pos(i * 4)
Next i
For i=1 To m
For j=1 To n
sum((i- 1) *n+ j) = sum((i- 1) * n+ j- 1) + flag((i- 1)*n+ j)
s=s+Str(sum((i-1)*n+j))
Next j
List1. AddItem s
Next i
End Sub
Sub add (ByVal x1 As Integer, ByVal y1 As Integer, ByVal x2 As Integer, ByVal y2 As Integer)
'按行标记地毯铺设情况
For i=x1 To x2
flag((i - 1) * n + y1) = flag((i- 1)*n+y1) + 1
Next i
End Sub
时间 |
第1小时 |
第2小时 |
第3小时 |
第4小时 |
第5小时 |
第6小时 |
第7小时 |
|
A城温度 |
30 |
30 |
33 |
33 |
31 |
31 |
32 |
|
A城数据 |
温度 |
30 |
33 |
31 |
32 |
|||
截止时间 |
2 |
4 |
6 |
7 |
||||
B城温度 |
20 |
20 |
20 |
22 |
21 |
21 |
22 |
|
B城数据 |
温度 |
20 |
22 |
21 |
22 |
|||
持续时长 |
3 |
1 |
2 |
1 |
||||
计算结果 |
温差 |
10 |
13 |
11 |
10 |
|||
持续时长 |
2 |
1 |
1 |
3 |
(时间单位:小时,温度单位:摄氏度)
表中,A城数据有4个记录,其中第1个记录为(温度30,截止时间2),第2个记录为(温度33,截止时间4),这表明从开始到第2小时的温度都是30,此后到第4小时的温度都是33。B城数据有4个记录,其中第3个记录为(温度21,持续时长2),这表明第5、第6这2个小时的温度都是21。两城温差计算结果的第4个记录为(温差10,持续时长3),这表明第5第6、第7这3个小时的温差都是10。
Const m =1000 ‘温度数据和温差数据包含的记录数都少于1000
Dim na As Integer, nb as integer ‘A、B城数据分别有na和nb个记录
Dim ha(m)As Integer ‘ha(i)存储A城第i个记录中的温度
Dim ta(m)As Integer ‘ta(i)存储A城第i个记录中的截止时间
Dim hb(m)As Integer ‘hb(i)存储B城第i个记录中的温度
Dim tb(m)As Integer ‘tb(i)存储B城第i个记录中的持续时长
Dim h(m)As Integer ‘h(i)存储计算结果第i个记录中的温差
Dim t(m)As Integer ‘t(i)存储计算结果第i个记录中的持续时长
Private Sub Command1_ Click( )
Dim i As Integer, j As Integer
Dim p0 As Integer, p1 As Integer, diff As Integer
Dim n As Integer ‘两城温差数据的记录个数
‘读取两城数据,存入变量ma,nb及数组ha,ta,hb,tb中,代码略
For i=2 To nb
tb(i)= ‘将B城第i个记录中的持续时长转换为截止时间
Next i
i=1 : j=1
n=0
p0=0
Do While i < na And i<= nb
diff ha(i)-hb(j)
p1 = ta(i)
IfThen i =i+1
If p1 >= tb (j) Then
p1 = tb(i)
j=j+1
End if
If n = 0 Or diff <> h(n) Then
n=n+1
h(n) = diff
t(n) = pl-p0
Else
End If
p0=pl
Loop
‘输出两城温差数据,代码略
End Sub