题目

质量为0.5kg的热水，温度从90℃降低到30℃，求这些水放出的热量。[水的比热容为4.2×103 J/（kg·℃）] 答案：【答案】1.26×105J【解析】Q 放＝cm（t0－t）＝4.2×103J/（kg·℃）×0.5kg×（90－30）℃＝1.26×105JMemories ________on him as soon as he met the friend whom he had not heard from for over thirty years. A．crowded in               B．resulted in C．joined in                D．got in