题目

如图所示，固定斜面倾角为θ，整个斜面分为AB、BC两段，且2AB=BC．小物块P（可视为质点）与AB、BC两段斜面之间的动摩擦因数分别为μ1、μ2．已知P由静止开始从A点释放，恰好能滑动到C点而停下，那么θ、μ1、μ2间应满足的关系是（ ）A. tanθ= B. tanθ= C. tanθ=2μ1－μ2 D. tanθ=2μ2－μ1 答案：【答案】A【解析】由动能定理tan θ＝，B对；【2012 贵州遵义】—How was your climbing Mount. Huang?—I didn’t believe I could do it _______ I got to the top.A. until while C. after