s=“Hello world”
s1=“”
n=Len(s)
For i=1 To n\2
If Mid(s, i, 1) > Mid(s, n-i+1, 1) Then
s1=s1 + Mid(s, i, 1)
Else
s1=Mid(s, n-i+1, 1)+s1
End If
Next i
Text1.Text=s1
执行该程序段后,在文本框Text1中显示的是( )
按照次序逆序输出并从小到大输出。提示:list.reverse(),list.sort()
若假定某用户一个月的用电量为x千瓦时,当前单价为p元/千瓦时,则计算标准如下:当x≤50时,电费为p×x元;当50<x≤200时,电费为p×x+(x-50)×0.03元;当x>200时,电费为p×x+4.5+(x-200)×0.1元。
程序设计界面如下图所示,程序的功能是:在文本框Text1中输入用电量x(单位:千瓦时),在文本框Text2中输入电量p(单位:元),单击“计算”按钮(Command1)后,在标签Label4中输出计算结果。
Private Sub Command1_Click()
Dim x As Single, p As Single
Dim s As Single
x =
p = '此处改错
If x <= 50 Then
s = p * x
s = p * x + (x - 50) * 0.03
Else
s = p * x + 4.5 + (x - 200) * 0.1
End If
Label4.Caption = "本月的电费为:" + + "元"
End Sub
改正:
每项任务有一个紧急程度,用数字表示,数字越大紧急程度越高。紧急程度最高的任务优先执行,紧急程度相同先出现先执行。若某项任务在执行过程中出现了一个紧急程度更高的任务,则正在执行的任务将被暂停,执行该紧急程度更高的任务。
编写VB程序,功能如下:程序运行时,各项任务数据按出现时刻升序显示在列表框List1中,单击“开始”按钮Command1,按照任务完成的先后顺序,在列表框List2显示每项任务的编号以及完成时刻。程序运行界面如图所示:请回答下列问题:
1号任务:时刻1出现,完成所需时长4,紧急程度1
2号任务:时刻2出现,完成所需时长2,紧急程度2
3号任务:时刻7出现,完成所需时长1,紧急程度3
则这3个任务的完成的顺序为(单选,填字母:A . 1号、2号、3号 /B . 2号、3号、1号 / C . 2号、1号、3号)。
Dim id(0 To 100) As Integer '任务编号
Dim t(0 To 100) As Integer '出现时刻
Dim L(0 To 100) As Integer '完成所需时长
Dim v(0 To 100) As Integer '紧急程度
Dim n As Integer '总任务数
Private Sub Form_Load()
'本过程读取任务编号、出现时刻、完成所需时长和紧急程度的数据分别存储在数组 id,t,L和v中,并在List1中显示,代码略
End Sub
Private Sub Command1_Click()
Dim q(0 To 100) As Integer 'q 数组按优先顺序存储已出现的任务编号
Dim k As Integer, i As Integer, j As Integer, cur As Integer
cur = 0: k = 0 'cur 记录当前时刻
For i = 1 To n
Do While k > 0 And t(i) >= cur + L(q(k)) '新的任务出现时,计算并输出已经完成的任务编号
List2.AddItem adj(2, (id(q(k)))) + adj(6, cur + L(q(k)))
cur = cur + L(q(k))
k = k - 1
Loop
If k > 0 Then L(q(k)) = '更新正在执行的任务的完成所需时长
k = k + 1
j = k
Do While v(q(j - 1)) >= v(i)
q(j) = q(j - 1)
j = j - 1
Loop
q(j) = i
Next i
Do While
List2.AddItem adj(2, id(q(k))) + adj(6, cur + L(q(k)))
cur = cur + L(q(k))
k = k - 1
Loop
End Sub
Function adj(x As Integer, v As Integer) As String
'adj可以通过添加前置空格将v转化为x位长度的字符串,便于输出对齐,代码略
End Function
请回答下列问题。
Constn= 10
Dim a(1 To n) As Integer
Private Sub Command1_ Click()
Dim Left As Integer, Right As Integer, Lstart As Integer, Rstart As Integer
Dim i As Integer, j As Integer, t As Integer, s As String
'随机生成n个不重复元素的数组a,并在左边环形显示,代码略
k= 1
For i= 2 Ton
If a(i) < a(k) Thenk=i
Next i
Lstart = (k+n- 2) Mod n+ 1: Rstart= k Mod n+ 1
i= 1
Do Whilei<= (n-1)\2
Left = Lstart
For j= 1 To
p= (Left+ n-2) Mod n+ 1
If a(Left) > a(p) Then
t= a(Left): a(Left) = a(p): a(p)= t
End If
Left= p
Next j
Rstart= Rstart Mod n + 1
Right = Rstart
Do While
p=RightModn+1
If Then
t= a(Right): a(Right) = a(p): a(p)=t
End If
Right= p
Loop
Lstart =
i=i+ 1
Loop
排序后的数据在右边环形显示,代码略
End Sub
如字符串“ABDAC”与字符串“AABCD”可以归为同一类,与“AABBC”不可以归为同一类。图图编写了一VB程序,功能如下:在文本框Text1中输入字符串s1,在文本框Text2中输入字符串s2,单击“判断”按钮Command1,在标签Label1中显示是否可以归为同一类的结果。部分运行界面如图所示。
请回答下列问题:
Private Sub Command1_Click()
Dim a(1 To 100) As Boolean
Dim i As Integer, j As Integer
Dim flag As Boolean
s1 = Text1.Text
s2 = Text2.Text
flag = True
For i = 1 To Len(s2)
Next i
If Len(s1) <> Len(s2) Then
flag = False
Else
For i = 1 To Len(s1)
c =
j = 1
Do While j <= Len(s2)
If Then
a(j) = False
Exit Do
End If
Loop
If j = Len(s2) + 1 Then flag = False
Next i
End If
If flag Then
Label1.Caption = "可以归为同一类"
Else
Label1.Caption = "不可归为同一类"
End If
End Sub
Dim a(1 To 5) As Integer
a(1) = 1
For i = 2 To 5
a(i) = Int(Rnd * 9) +1
If a(i) Mod 2 = 1 Then
a(i) = a(i) + a(i - 1)
ElseIf a(i) mod 2 = 0 Then
a(i) = a(i) / 2
End If
Next i
执行程序后,a 数组各元素不可能是( )
Dim i As Integer
Dim c As String, s As String, t As String
s = "2021 PYthon": t = ""
For i = 1 To Len(s)
c = Mid(s, i, 1)
If c >= "a" And c <= "z" Then
t = t + c
ElseIf c >= "0" And c <= "9" Then
t = c + t
End If
Next i
Text1.Text = t
执行该程序段后,文本框Text1中显示的内容是( )
s = "Happy new year↑”
flag=False:m=0
For i=1 To Len(s)
c= Mid(s,i,1)
If c >=“a" And c <= "z” Then
If Not flag Then
m=m+1
flag=True
End If
Else
flag = False
End If
Next i
a=100
a=a+1
a=“abc”
你能告诉这个同学变量a到底存储的是哪个量吗?( )
from random import randint
n=input("请输入一串数字:")
k=randint(0,len(n)) #randint用于随机生成[0,len(n)]之间的整数
for i in range(k):
for j in range(len(n)-1):
if n[j]>n[j+1]:
break
else:
n=n[:len(n)-1]
continue #continue跳过当前循环的剩余语句,直接进行下一轮循环
n=n[:j]+n[j+1:]
执行该程序段后,输入“1529”,则变量n可能是( )
s=['seashell', 'gold', 'brown', 'purple', 'tomato']
print(s[2][1:4])