题目

Hello everybody,      I teach adult English in a business school in Cuba. My students will go in for foreign trade. I would like to know other teachers in my field to exchange information. I would like to meet many other teachers. Jorge L. Yong Hello everyone,      I am a Canadian ESL teacher. Some of my students (aged 15-17) would like to have e-pals and exchange ideas through email. I think it is a great idea! We could also eventually send you videos of our school, village and so on. If interested, please email tibibri@hotmail.com.       Hope to hear from some of you very soon.工业上电解海水(含氯化钠)可以得到多种化工产品，同时能处理含二氧化硫的废气，该流程如下图所示。下列说法正确的是Ａ．该流程中有两种单质Ｂ．图中反应①属于分解反应Ｃ．反应中硫元素的化合价发生变化Ｄ．从海水中最终得到“NaCl(产品)”的过程是物理变化 A 【解析】A、氢气和氧气是单质，故A正确； B、根据生成物为氢氧化钠溶液、氯气、氢气，海水为反应物，则化学反应式是 2NaCl+2H2O 2NaOH+Cl2↑+H2↑，不符合分解反应的定义，故B错误； C、反应物二氧化硫中硫元素的化合价是+4价，化合物中硫元素的化合价还是+4价，化合价没有发生变化，故C错误； D、从海水最终得到NaCl（产品）的过程可知，每一步都有...