已知sinα、cosα是关于x的方程x2-ax+a=0的两个根(a∈R),(1)求sin3θ+cos3θ的值;(2)求tanθ+的值. 答案:解:依题意由Δ≥0,即(-a)2-4a≥0,得a≤0或a≥4且①2+②×2,得a2-2a-1=0,∴a=1-或a=1+(舍).∴sinθ+cosθ=sinθcosθ=1-.(1)sin3θ+cos3θ=(sinθ+cosθ)(sin2θ-sinθcosθ+cos2θ)=(1-)[1-(1-)]=-2.(2)tanθ+=,∴tanθ+=.
________, I have never seen anyone who’s as capable as John.
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A.As long as I have traveled
B.Now that I have traveled so much
C.Much as I have traveled
D.As I have traveled so much