一辆汽车沿平直公路以V0= 10m/s匀速运动,忽然以加速度为2m/s2刹车,求汽车刹车后6s内的位移是多大? 答案:25m 解析: 设汽车刹车后到停止运动用时,则: 由 可得: =5 s 因为t=12s>=5 s 所以汽车刹车后12s的位移就是前5s的位移 S= Our team’s success was ________ the efforts of Mr. Mark, who is ________ arrive here in ten minutes. A. because; due to B. because of; about to C. due to; due to D. as a result; going to