题目

如图为一直角三角形纸片，∠C=90°，两直角边AC=6㎝，BC=8㎝，现将直角边AC沿直线AD折叠，使它落在斜边AB上，且与AE重合，求CD的长  答案：解：由勾股定理求得AB=10㎝；-------------------2分由折叠性质可知AE=AC=6㎝，CD=DE, ∠AED=∠C   ∴BE=10-6=4㎝；-------------------------------5分设CD=DE=，根据勾股定理得解得=3.答：CD的长是3.--------------------------------8分 解析:略 It was ____ he broke the law that he was sentenced to six years’ imprisonment. A. that        B. as         C. because       D. for