题目

如图，在△ABC中，∠B＝26°，BC的垂直平分线分别交AB，BC于点D，E．若CA＝CD，求∠ACB的度数． 答案：解：直线DE垂直平分BC．∵DB＝DC，∴∠B＝∠DCB＝26°，∴∠ADC＝∠B+∠DCB＝52°，∵CA＝CD，∴∠A＝∠ADC＝52°，∴∠ACD＝180°﹣∠A﹣∠ADC＝76°，∴∠ACB＝76°+26°＝102°． －You are always full of ________．Can you tell me the secret? －Taking plenty of exercise every day． [　　] A． power B． strength C． force D． energy