题目

如图,在正方形ABCD外作等腰直角△CDE,DE=CE,连接AE,则sin∠AED=    .   答案:解:过A点作AG⊥ED,如图: 设正方形ABCD的边长为a, ∵等腰直角△CDE,DE=CE, ∴DE=a,∠CDE=45°, ∴△AGD也是等腰直角三角形, ∴AG=GD=a, ∴AE=, ∴sin∠AED=,   ______ by a snake, she was frightened of it.A.Being bittenB.To biteC.Having been bittenD.Biting
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