题目
已知关于x的方程ax2+bx+1=0的两根为x1=1,x2=2,则方程a(x+1)2+b(x+1)+1=0的两根之和为__________. 答案:【答案】1【解析】利用整体的思想以及根与系数的关系即可求出答案.设x+1=t,方程a(x+1)2+b(x+1)+1=0的两根分别是x3,x4,∴at2+bt+1=0,由题意可知:t1=1,t2=2,∴t1+t2=3,∴x3+x4+2=3故答案为:1根据所给单词完成句子。要求符合语法,语句通顺,大小写正确,单词不得重复使用,标点已给出。
1.better, are, feeling, you
____________________________________________________?
2.people, are, what, they, kind
____________________________________________________!
3.does, which, in, live, building, Jenny
____________________________________________________?
4.cost, the money, didn’t, dictionary, much,
me
____________________________________________________.
5.lend, Sam, MP5, to, I, yesterday, my
____________________________________________________.