题目

函数y=log0.3(x2－2x)的单调递减区间是 A.(－∞,1)                                                       B.(－∞,0)C.(1,+∞)                                                       D.(2,+∞) 答案：解析:由x2－2x＞0得x＞2或x＜0.而0.3＜1,t=x2－2x的递增区间(2,+∞)即为所求.答案:D–I think the teacher should give Ted one more chance. --Yes, it’s not his fault to miss the bus.A．anotherB．another oneC．onceD．one another