题目

若函数f(x-1)=x2-2x+3(x≤1)，则函数f-1(x)的草图是(    ) 答案：解析:f(x-1)=(x-1)2+2          ①     f(x)=x2+2.                          ②    又∵①式中,x≤1，∴x-1≤0.故②式中函数自变量x≤0.由②式得x=-，即f-1(x)=-(x≥2).答案:CHow many _______ do you want?A. milk B. fruit C. banana D. apples