题目

(16)函数y=loga(x+3)-1(a＞0，a≠1)的图象恒过定点A，若点A在直线mx+ny+1=0上，其中mn＞0，则的最小值为         . 答案：答案:8解析:y=loga(x+3)－1的图象恒过定点A(－2，－1).∵A在直线mx+ny+1=0上，∴－2m－n+1=0,即m+=.∵mn＞0,∴m＞0,n＞0.∵≥+ (a、b∈),∴≥.∴≥8，当且仅当m==，即m=，n=时，取“=”.∴的最小值是8.  第Ⅱ卷(客观题 共35分) 一、根据语境、首字母或汉语提示写出词汇(共2分) 76. How many people p__________ in the opening ceremony? 77. Everyone should o________ the traffic rules.. 78. Would you please do me a f_______ to push the car to start. 79. As a _________(目击者), he gave the police a vivid description of the accident.