题目

在常温下,某溶液中由水电离出的c(H+)= 1× 10﹣11 mol • L﹣1,下列说法中正确的是 A.该溶液肯定显碱性B.该溶液肯定显酸性 C.该溶液的pH可能是11,也可能是3D.该溶液的pH肯定不是11 答案:【答案】C 【解析】首先要掌握本题中,由水电离出的c(H+)水 = 1×10-11 mol • L﹣1,则由水电离出的c(OH-)水=1 × 10-11 mol • L﹣1。如在酸溶液中,c(OH-)溶液= c(OH-)水=1×10-11 mol • L﹣1,此时c(H+) = 1 × 10-3 mol • L﹣1,pH=3,溶液显酸性;又如在碱溶液中c(H+)溶液=c(H+)水=1×10-11 mol • L﹣1,此时溶液的pH = ll,溶Though she has been in England for half a year, she is still unable to _____ in simple English. A. explain herself         B. express herself   C. speak her mind         D. make herself understand
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