铁镍蓄电池又称爱迪生电池,放电反应 Fe+Ni2O3+3H2O=Fe(OH)2+2Ni(OH)2 则下列说法正确的是 A. 电池的电解液为酸性溶液,正极为Ni2O3、负极为Fe B. 电池充电过程中,阴极附近溶液的pH降低 C. 电池放电时,负极反应为Fe+2OH--2e-= Fe(OH)2 D. 电池充电时,阴极反应为2Ni(OH)2+2OH-=Ni2O3+3H2O+2e- 答案:C I to Cape Town so I know nothing about it. A.don't travel B.won't travel C.haven't traveled D.hadn't traveled