题目

(1) 计算: (2) 先化简,再求值: ,其中 . 答案:解:) |−2|+9−20190−2sin30° =2+3−1−2×12 =2+3−1−1 =3 ; 解: (a2−2aa2−4a+4−3a−2)÷a2−9a−2 =[a(a−2)(a−2)2−3a−2]⋅a−2(a+3)(a−3) =(aa−2−3a−2)⋅a−2(a+3)(a−3) =a−3a−2⋅a−2(a+3)(a−3) =1a+3 , 当 a=1 时,原式 =11+3=14 .?Would you like to go to the concert with me? ?I'd love to, ________ I can't. I have a lot of homework to do. A. or B. but C. so D. and
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