如图,直线AB,CD相交于点O,EO⊥CD于点O,FO⊥AB于点O.若∠AOE=50°,求∠BOC和∠COF. 答案:解:∵EO⊥CD于点O,∴∠DOE=90°,∴∠AOD=∠DOE﹣∠AOE=90°﹣50°=40°,∴∠BOC=∠AOD=40°,∵FO⊥AB于点O,∴∠BOF=90°,∴∠COF=∠BOF+∠BOC=90°+40°=130°.Jane said to Mary, “What are you going to do tomorrow?”Jane asked Mary ___________.A.what was she going to do the next dayB.what she was going to do tomorrowC.what she was going to do the next dayD.what was she going to do tomorrow