题目
一次函数y=kx+b的图象如图所示,则k、b的值为( ) A.k>0,b>0 B.k>0,b<0 C.k<0,b>0 D.k<0,b<0 答案:A【考点】一次函数图象与系数的关系. 【分析】先根据一次函数y=kx+b的图象过一、三象限可知k>0,由函数的图象与y轴的正半轴相交可知b>0,进而可得出结论. 【解答】解:∵一次函数y=kx+b的图象过一、三象限, ∴k>0, ∵函数的图象与y轴的正半轴相交, ∴b>0. 故选A. 【点评】本题考查的是一My brother ________ while he ________ his bicycle and hurt himself.
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A.fell, was riding
B.fell, were riding
C.had fallen, rode
D.had fallen, was riding