(本小题满分10分) 已知、是圆与轴的两个交点,是圆上的动点,连结并延长至,使||=||,求与的交点的轨迹方程. 答案:解:设,则 ① 因为 |CD|=|BC|,所以C是BD的中点, 又O是AB的中点 所以P是的重心, 由已知可得,且A(-1,0)、B(1,0) 因此,解得 ② 将②代入①得 化简,得 因此,P的轨迹方程为()--- Where is my dictionary? I remember I put it here yesterday. --- You _____ it in the wrong place. A.must put B.should have put C.might put D.might have put