某有机物分子式为C5H10O3,与饱和NaHCO3溶液反应放出气体体积与同等状况下与Na反应放出气体体积相等,该有机物有(不含立体异构)( ) A. 9种 B. 10种 C. 11种 D. 12种 答案:【答案】D 【解析】 【分析】 分子式为 C5H10O3与饱和 NaHCO3 溶液反应能放出气体,说明含有羧基,且 1molC5H10O3 与足量钠反应 放出 1mol 气体,说明分子中含有羟基,可看作-OH取代C4H9-COOH中C4H9-的H原子。 【详解】分子式为 C5H10O3与饱和 NaHCO3 溶液反应能放出气体,说明含有羧基,且 1molC5H10O3 与足量钠反应 ______ about wild plants that they decided to make a trip to Madagascar for further research A. so curious the couple was B. So curious were the couple C. How curious the couple were D. The couple was such curious