题目

如图，在△ABC中，∠ABC和∠ACB的平分线交于点D，过点D作EF∥BC交AB于E，交AC于F，若AB=12，BC=8，AC=10，则△AEF的周长为（ ）A. 15 B. 18 C. 20 D. 22 答案：【答案】D【解析】利用平行和角平分线的定义可得到∠EBD=∠EDB，所以可得ED=EB，同理可得DF=FC，所以△AEF的周长即为AB+AC，可得出答案．∵EF∥BC，∴∠EDB=∠DBC，∵BD平分∠ABC，∴∠ABD=∠DBC，∴∠EBD=∠EDB，∴ED=EB，同理可证得DF=FC，∴AE+AF+EF=AE+EB+AF+FC=AB+AC=22，即△AEF的周长为22，故选：D.__ has been mentioned above, continued chairman after he took a sip of coffee, ____ the project must be carried out before spring flood comes.   A. As; that        B. That; which    C. This; which     D. It; that