题目

△ABC的内角，A，B，C的对边分别为a，b，c，已知a＝bcosC＋csinB. (1)求B； (2)若b＝2，求△ABC面积的最大值． 答案： (1)由已知及正弦定理，得sinA＝sinBcosC＋sinCsinB.                       ① 又A＝π－(B＋C)， 故sinA＝sin(B＋C)＝sinBcosC＋cosBsinC.                                      ② 由①②和C∈(0，π)，得sinB＝cosB. 又B∈(0，π)，所以B＝. .….….….….….….….….…6分 ②△ABC的面积S＝acsinB＝---What about going abroad for further study? ---Great, but I never expected ______ a chance for me before. A. there being B. there to be　　　　 C. there is　 D. there are