已知两向量a=(2λ,-1),b=(-2,1),λ∈R, (1)若2a+b与a-2b平行,求λ的值; (2)若2a+b与a-2b垂直,求λ的值. 答案:解析:∵a=(2λ,-1),b=(-2,1), ∴2a+b=(4λ-2,-1),a-2b=(2λ+4,-3). (1)当2a+b与a-2b平行时,有(4λ-2)·(-3)=(-1)·(2λ+4), ∴-12λ+6=-2λ-4.∴10λ=10. ∴λ=1. (2)当2a+b与a-2b垂直时,有(2a+b)·(a-2b)=0, ∴(4λ-2)(2λ+4)+(-1)×(-3)=0,即8λ2+12λ-5=0.∴λ=.—Are you going to find a job or go on with your study to get a doctor’s degree? —I have had enough of ______ life. I want to find a job. A. ridiculous B. appropriate C. straightforward D. academic